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# 2520 is the smallest number that can be divided
# by each of the numbers from 1 to 10 without any remainder.
# What is the smallest positive number that is evenly
# divisible by all of the numbers from 1 to 20?
# Euclid's algorithm for the greatest common divisor
def gcd(a, b)
b.zero? ? a : gcd(b, a % b)
end
# Calculate the LCM using GCD
def lcm(a, b)
(a * b) / gcd(a, b)
end
result = 1
20.times do |i|
result = lcm(result, i + 1)
end
p result